0208 days. date_from, evnt. DATEDIFF with examples DATEDIFF function accepts 3 parameters, first is datepart (can be an year, quarter, month, day, hour etc. Consider SQL Server function to calculate the difference between 2 dates in months: SQL Server : -- Difference between Oct 02, 2011 and Jan 01, 2012 in months SELECT DATEDIFF ( month, '2011-10-02', '2012-01-01') ; -- Result: 3. 2425. This command prints the order date in the specified format. S is milliseconds in one or up. 1 Answer. Functions, you can call DateDiffDay: var ans = from t in Table1 group t by 1 into tg select tg. Here is example with 23 hours difference: select CONVERT (VARCHAR, DATEDIFF (dd, '2018-04-12 15:54:32', '2018-04-13 14:54:32')) + ' Days ' + CONVERT (VARCHAR, DATEDIFF (hh, '2018-04-12 15:54:32', '2018-04-13 14:54:32') % 24) + ' Hours ' But the. DateValue > DateAdd (day,-3,getdate ()) doing this in this way makes your. CASE WHEN a. ;-). Summary: in this tutorial, you will learn how to use the SQL DATEPART () function to return a specified part of a date such year, month, and day from a given date. DATEADD () Adds or subtracts a specified time interval from a specified date. ADD_MONTHS returns slightly different results than DATEADD used with a MONTH component:. The solution takes as base the first known date by SQL Server (1900-01-01). In PostgreSQL there are basically 2 functions to do the same, as we have both date_part and extract: SELECT current_date AS ACTUAL_DATE, EXTRACT (DAY FROM current_date) AS ACTUAL_DAY, EXTRACT (MONTH FROM current_date) AS ACTUAL_MONTH, EXTRACT (YEAR FROM current_date) AS ACTUAL_YEAR. The system calculates the number of complete months between given dates. 構文 @DATEDIFF (' difference ', ' date ', ' date ') difference. 2258064516. Few examples of DATEDIFF: DATEDIFF - Example 1 Here, in this example, datepart is "day": SELECT DATEDIFF(day,'2016-06-05','2016-08-05') AS DiffDate. NEW_TIME (date, timezone1, timezone2) Timestamp. sql. 25)) AS `numberofemployees`. (INTCK returns a negative value whenever the first date is. 1. INTERVAL '15' MINUTE. Assuming that a. NEXT_DAY: Returns a datetime value that represents the first weekday, named by string-expression, that is later than the date inexpression. format_datetime(timestamp, format) → varchar. Teams. buf 1 declare 2 total_days integer; 3 total_weeks integer; 4 remaining_days integer; 5 begin 6 total_days := date '2014-12-16' - date '2014-12-01'; 7 total. So in order to get specific type of delivery for the last 3 months I was thinking to get today's date and convert it to 01/mm/yyyy format and ref it with the delivery month in the table to get least 3 month including. Date2Date. The math is 100% accurate for dates within a couple of hundred years or so. January=1, February=2, etc. How To turn a string with "pipe-separated" values into individual rows in Oracle PL/SQL. month). Delaying Execution. It takes into account the fact that DATEDIFF() computes the difference without considering what month or day it is (so the month diff between 8/31 and 9/1 is 1 month) and handles that with a case statement that decrements the result. In SQL Server, there is a function datediff with datepart 'q'/quarter which behaves as follows :--. Share. g. Start learning SQL now ». 365 / 365. Sum (r => EF. Simply i need to convert this: SELECT FLOOR(DATEDIFF(NOW(),`startdate`)/365. DECLARE @date datetime2 = '2021-01-07 14:36:17. 999 would get rounded up to the next day anyway. As shown clearly in the result, because 2016 is the leap year, the difference in days between two dates is 2×365 + 366 = 1096. MONTHS_BETWEEN(p1, p2) DATEDIFF( MONTH, CAST(p2 AS float), CAST( DATEADD(DAY, ( -CAST(DATEPART(DAY, p2) AS float(53)) + 1 ), p1) AS float)) Round a Date to a Specific Unit of Measure. Date parts examples are day, week,. here i am trying get the month differences between two. 25 = 0. Current Date/Time. So, this expression converts SYSDATE to a string, using whatever local settings are on your system. Answer: You can use the months_between function and convert it easily yo years between and decades between two dates: months_between/12 = years between. FROM_DAYS(): This function finds the date from the specified numeric date value. Commonly used datepart units include month or second. We would like to show you a description here but the site won’t allow us. PostgreSQL. Syntax %DateAdd(date_from, add_days) Description. select datediff (q,'03-30-2005','04-01-2005') will return 1. select sysdate - date '2022-01-03' as delta from dual; The resulting value on the day I am running this is 37. If they are identical down to the second then, presumably, returning 0 is the right. 208333, so the value is correct! So now that we know how subtracting dates. DiffYears Returns the difference in years between two dates. Sample table: ProductID Date P101 31-DEC-2012 P102 29-DEC-2011 DateDiff is not a function that exists in Oracle. 5 = 0. DATEDIFF(interval, date1, date2) Parameter Values. Modified 1 year, 3 months ago. 99. The DATEDIFF() function returns the number of days between two date values. SELECT DATEADD ( year, DATEDIFF ( year, 0, GETDATE ()), 0 ) 這個 SQL 的技巧是先取得和 1900-01-01 - 也就是上面的 0 的意思，SQL Server 中的第零天 - 差幾年 (從 DATEDIFF 得到一個整數)，再用 DATEADD 加 0 來將整數再轉成日期的型態。. The months_between function returns the elapsed months going from the second date to the first. you can check against last 90 days. This works as Oracle will perform an implicit cast (using TO_TIMESTAMP( time, format_mask )) using the session parameter. In Oracle SQL, I want to display the difference between two dates in the format 'x years y months z days'. select dateadd(ms,-3,DATEADD(mm, DATEDIFF(m,0,getdate() )+1, 0)) Last Day of Current YearRemarks. For example, suppose you have values below the start and end times. *You may also use the DATEDIFF function. NEXT_QUARTERDECLARE @gapPeriod DATETIME = DATEADD(MONTH,-2,GETDATE()); --Period:Last 2 months. Oracle doesn't have a DATEDIFF() function. I have a table where PurchasedDate is maintained. The Question asked for "6 months from the system date". Now for testing purposes I need to compare the data for the last say 4 months from the sysdate. Last 3 Months. If the endDate has a day part less than startDate, it will get pushed to the previous month, thus datediff will give the correct number of months. parse_datetime(string, format) → timestamp with time zone. current_timestamp() returns the timestamp on the database client side. 1. The add_days variable can be negative. ). The function INTCK ('MONTH','1feb1991'd,'31jan1991'd) returns –1 because the first date is in a later discrete interval than the second date. For ex. Here is the TSQL to calculate the last day of the current month. It is the unit in which the DATEDIFF() function returns the difference between a start date and an end date e. SET @as_of = GETDATE() SET @bday = 'mm/dd/yyyy' (0 + Convert(Char(8),@as_of,112) - Convert(Char(8),@bday,112)) / 10000. - Find the “date_diff” in minutes and add it with the “date_diff” in hours and the “date_ diff” in days. MySQL DATEDIFF: Calculating weeks, months, or years between two dates. So if there are two dates separated by one day, the year difference can be 1 (see select datediff (year, '20141231', '20150101') ). Also, according to Oracle's documentation LAST_DAY returns a DATE. mysql> SELECT EXTRACT (DAY FROM "2021-10-24") AS SHOW_DAY; Here, we have written a SELECT query with the EXTRACT () function to get the day from the given date. SQL date formatfunctions in SQL server are really powerful and really helps to deliver impactful data analytics and reports. That prevents. Note that SQL Server DATEDIFF(month, date2, date1) function does not return exactly the same result, and you have to use an user-defined function if you need to fully emulate the Oracle MONTHS_BETWEEN function (see. LeapYear Returns one (1) if the specified year is. DateDiffDay (r. The Oracle NEXT_DAY() function returns the date of the first weekday specified by day name that is later than a date. ArrivalDate, Trips. DATE is the main – or rather, original – datatype used in Oracle for holding dates. datediff isn't a function in Oracle. I am looking for solution how to select number of days between two dates without weekends and public holidays. SELECT DATEDIFF (YY, DateOfBirth, GETDATE ()) - CASE WHEN RIGHT (CONVERT (VARCHAR (6), GETDATE (), 12), 4) >= RIGHT (CONVERT (VARCHAR (6), DateOfBirth, 12), 4) THEN 0 ELSE 1 END AS AGE. So, there’s. Formats timestamp as a string using format. Accountnumber = T1. If IsDate (startdate) and IsDate (enddate) Then. select (dt1-dt2) * 24 * 60 * 60 from t; dt1-dt2 gives diff in days (eg: 1. In this article, we learned how to do SQL subtract dates using the DATEDIFF function. Use DATEADD and DATEDIFF() function together in SQL query. Both integer (int) and big integer (bigint) are numeric data types used to store integer values. Join our newsletter and get access to exclusive content every month. Functions. Improve this answer. 1. Goal. Examples of Results in Months. Share. COMPUTE days2 = DATEDIFF(date2,date1,"days"). 天：. txt","contentType":"file"},{"name. MySQL :: MySQL 5. Sorted by: 55. Must be one of the values listed in Supported Date and Time Parts (e. SYSTIMESTAMP). This function helps to retrieve any particular value of the timestamp in any format that we wish. It would need to be EndDate + 23:59:59. End date will be sysdate. 4193548 The number of whole months can be split into. This function adds a number (a signed integer) to a datepart of an input date, and returns a modified date/time value. So given Netezza is based on PostgreSQL, so it's AGE function, is equivalent to Snowflake's DATEDIFF, but like PostgreSQL interval it defaults to expressing it in simplified terms of Years/Months/Days. If you want to format it as you wanted (note that mm format mask is for months; mi is for minutes), then you could do some extracting - again from timestamp (won't work for date):. Date 2: 1st Feb 2011. SQL> ed Wrote file afiedt. see this sqlfiddle. The values to compare. Returns 'Oracle Database 10g Enterprise Edition Release 10. Oracle DATEDIFF函数在Oracle中的使用 在本文中，我们将介绍Oracle数据库中的DATEDIFF函数。 阅读更多：Oracle 教程 什么是DATEDIFF函数？ DATEDIFF函数用于计算两个日期之间的时间间隔。它可以在Oracle数据库中使用，并返回一个整数值，表示两个日期之间的差异。这对于计算两个日期之间的天数、小时数、分钟. Before using this function, you must set the NLS_DATE_FORMAT parameter to display 24-hour time. g. Modified 3 months ago. So, the difference between Jan 1 20015 and Dec 31 2016 is 1 year. By adding 1 month, I am calculating the first day of next month and then subtraction 3 milliseconds, which allows me to arrive at the last day of the current month. Instead, you can use simple arithmetic with Oracle dates, where subtracting one date from another gives the number of days, and where you can add an subtract days from a given date. We’re calculating months of service in this example. However, The problem is different number of records because DATEDIFF(month,a,b)<=4 in SQL Server returns only the month difference whereas months_between(a,b)<=4 in oracle returns the. Improve this answer. The DATEDIFF function does not calculate the difference in months based on days. DATEDIFF does not guarantee that the full number of the specified time units passed between 2 datetime values: -- Get difference in hours between 8:55 and 11:00 SELECT DATEDIFF (hh, '08:55', '11:00'); -- Returns 3 although only 2 hours and 5 minutes passed between times -- Get difference in months between Sep 30, 2011 and Nov 02, 2011. TIMESTAMP Functions. DATEDIFF(MONTH, 0, GETDATE())-1, 0) AND DATEADD(MONTH, DATEDIFF(MONTH, -1, GETDATE())-1, -1) based on the comment below I have modified the query. I've tried Datediff(day, start_date, end_date), but I was prompt with: invalid column name. (year/month/date from date) //oracle function for extracting values from date. DATEDIFF is built to return the number of date BOUNDARIES that are crossed. 242199 assumes that you want the number of solar years between 00:00 on the first date and 00:00 on the second date, to 9 significant figures. Syntax:DATEDIFF Examples Using All Options. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. The month and the last day of the month are defined by the parameter. To calculate the number of days between date1 and date2, you can use either Day of. Month difference between two dates in sql server. The datepart value cannot be specified in a variable, nor as a quoted string like 'month'. If you are familiar with Microsoft SQL Server functions but are new to Oracle databases, see Character Functions to compare SQL functions support in Microsoft SQL. 3. The Question asked for "6 months from the system date". S is milliseconds in one or up to six digits. ReturnDate) AS nvarchar(max)) END) AS [Duration] As a side note: I used nvarchar(max) for consistency with the first part of your query. This function adds a specified number of days, months, and years to a given date. columns c puts a limit on how many dates are returned. I want to calculate the current Age from Date of Birth in my Oracle function. The result is formatted according to the Format parameter. Then it subtracts a year if the birthdate hasn't passed. Assuming that a. g. DD is a two-digit day of the month (01 through 31). 3. Oracle Month to Date:Showing data 6 months greater than date parameter?? 607634 Mar 24 2010 — edited Mar 24 2010. The table contains the data about each staff member’s. Oracle常用函数:DateDiff () 返回两个日期之间的时间间隔自定义函数. Possible values: text representing an entry in the IANA time zone database. Using datediff in oracle. 4k 4 4 gold badges 40 40 silver badges 53 53 bronze badges. Tip 032: Summary of Date Functions. 首先在oracle中没有datediff ()函数. This conversion uses the NLS_DATE_FORMAT parameter to decide the format of the output string. Select name,surname from students. Improve this answer. Then, we need a 2-digit month string. 1. 2188940092 Example 2 Date 1: 10th March 2011 Date 2: 1st Feb 2011 MONTHS_BETWEEN = 1. 6. The result only contains the year, month and day, not the time. Now it only runs DateAdd () once, and it can use an index (if one exists), to only load the rows that match the predicate criterion. inner select select DATEDIFF(MONTH, 0, GETDATE()) will give the number of months from 1900-01-01 here it is 1350. For example, this function returns 1. Of course, if you need days instead of months, you can simply subtract one date from another, e. DATEDIFF is a common function in the SQL Server to find the number of days between two dates. DATEDIFF accepts either. CREATE FUNCTION trunc_date (@date DATETIME) RETURNS DATETIME AS BEGIN SELECT CONVERT (varchar, @date,112) END. The default is date format 1. 0. I have a creation date column in the table. 40 hours. Start date will. StartTime: 2022-27-27 14:00:00 EndTime:2022-12-12 19:30:00 Firstly, to find the time difference, we will use. This question was incorrectly asked. Viewed 44k times 3 I've got 2 date columns in my table (start_date, end_date). DATE_SUB () Subtract a time value (interval) from a date. DateGroup. The MDX DateDiff function for Essbase returns the difference (a number) between two input dates in terms of the specified date-parts, following a standard Gregorian calendar. Weeks. then the following should be the result. Expressions that return a value of any of the following built-in data types: a date, a timestamp, a character string, or a graphic string. g. For example, you might use DateDiff to calculate the number of days between two dates, or the number of weeks between today and the end of the year. February 28 and March 31), the fractional portion is zero, even if the days of the month are not the same. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). date_to) * 2) - CASE WHEN DATEPART(DW, evnt. 7 Reference Manual :: 12. Improve this answer. Based on Andriy's eagle-eyes, here is (I think) the DB2 syntax: WHERE d_date > current_date - 6 MONTHS. In this tutorial, you have learned how to use the Oracle INTERVAL data type to store periods of time in the tables. 2. * FROM #HRAL h INNER JOIN #LAZY_DATE_DIM dd ON dd. In SQL, we can add or subtract days, months, or years to a date by using the DATEADD function. The SQL code is "where fac. Tdy. Oracle SQL - CASE in a WHERE clause. There are many tricks to generate rows in Oracle Database. SQL> select 24 * (to_date ('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date ('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours from dual; DIFF_HOURS ---------- 2. In addition, with DATEDIFF () the column is an argument to the function. DateDiff(“m”, Fields! starting date. This works, but it is a bit clumsy compared to the sql server function:So, the weird number you see is the difference between the two dates. I used the following code: SELECT h. Apr 5, 2021 at 15:55. Example Getting the months and years between two dates using Datediff There is a round up issue with the Datediff function. The first one involves getting the difference in days and then converting it to 'x year y month z days'. 5. Month-difference between any given two dates: Have a look at the TIMESTAMPDIFF () function in MySQL. 997 to avoid that. CODE = 'CONTACT_CLIENT' THEN a. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. ) and rest are two dates which you want to compare. The date calculator calculates the difference between the 'Start Date' and 'End Date' and displays it in terms of the number of years, months, weeks and days between them. date + time. Using DbFunctions, accessed via EF. I suggest to use "months_between" function because it takes leap years into account (months_between wants 2 dates as parameters): select months_between(sysdate, to_date('1994-08-13', 'YYYY-MM-DD'))/12 from dual; 26,4729751904122. adddate addtime curdate current_date current_time current_timestamp curtime date datediff date_add date_format date_sub day dayname dayofmonth dayofweek dayofyear extract from_days hour last_day localtime localtimestamp makedate maketime. g. ) that are available and in this tutorial, we look at how to use the DATEADD function in SQL queries, stored procedures, T-SQL scripts,. 00. Based on the spreadsheet above, the following Excel function would return the following values:In Oracle, the datetime system function is SYSDATE. lastModified - w. @WernfriedDomscheit YYYY-MM-DD is not a date it is just a formatted string. Month([EndDate]) - DateMonth([StartDate]) Regards, Pat29 Answers. Then it would also be helpful to be able to. SELECT floor ( months_between ( date_1, date_2 )/12) floor_years_between FROM employee. two-digit days. For example, from 2/10 to 3/10 is considered one month, and from 2/10 to 3/15 is also. Difference of two dates in months. If date1 is earlier than date2, then the result is negative. lastModified - w. from a date time value. For both DATEDIFF and minus sign: Output values can be negative, for example, -12 days. select (dt1-dt2) * 24 * 60 * 60 from t; dt1-dt2 gives diff in days (eg: 1. Another example is to get the month of. As GMB has mentioned in the comment above, date functions depend on the database type you are using. Viewed 43k times 0 I want to. date_open END. So then in DATEADD(month, DATEDIFF(month, 0, GETDATE()), 0) that same number of months is added back to 1900-01-01 to get the start of the current month. Only 10+ years later - here's a db<>fiddle which demonstrates the difference between subtracting a date from a date (e. We are now using NHibernate to connect to different database base on where our software is installed. DATEADD(datepart,number,date) The DATEPART() function is used to return a single part of a date/time, such as year, month, day, hour, minute, etc. @Bruno - If the data types are TIMESTAMP WITH TIME ZONE, the interval that results from subtracting the two should take care of any time zone/ daylight savings time conversion. 3. DATEADD ('week', 1, [due date]) Add 280 days to the date February 20, 2021. DECLARE @yourDate DATE = '20160229' select DATEADD (MONTH, DATEDIFF (MONTH, -1, @yourDate)-1, -1) Just a note: this does remove any time portion in the input date, which may or may not be desired. The syntax for DATEDIFF is pretty straightforward: DATEDIFF (datepart, startdate, enddate) Let’s explore the parameters used here: datepart: The unit of time you want to use for the calculation, like year, quarter, month, day, or even smaller units like hour, minute, or second. If you are using MySQL there is the DATEDIFF function which calculate the days between two dates: SELECT dtCreated , bActive , dtLastPaymentAttempt , dtLastUpdated , dtLastVisit , DATEDIFF (dtLastUpdated, dtCreated) as Difference FROM Customers WHERE (bActive = 'true') AND (dtLastUpdated > CONVERT (DATETIME,. The function supports units of years, quarters, months, weeks, days, hours, minutes, seconds, milliseconds, microseconds, and nanoseconds. The system calculates the number of complete months between given dates. 1. Dates are always a joy to work with in any programming language, SQL not excluded. JohnD JohnD. Again, the expected results would be a value of 1. For example: 11/30/2004 through 04/30/2006. If date1 is later than date2, then the result is positive. Converting Valid Character Strings to Dates, Times, or Timestamps. Admission_Date) > 5. This is from my own library, will return the difference of months between two dates. DECLARE @yourDate DATE = '20160229' select DATEADD (MONTH, DATEDIFF (MONTH, -1, @yourDate)-1, -1) Just a note: this does remove any time portion in the input date, which may or may not be desired. Here’s the syntax for the DATEADD function: DATEADD (interval, number, date); The interval. e. Here is an example that uses date functions. The date functions are summarized in the table below. The days are in two different, adjacent months, so the answer is 1 month difference. Just divide the total by 7 to get the weeks and then calculate the remaining days. 1. Examples of Results in Months. SELECT DATE '0016-08-03' - DATE '2016-07-08' FROM dual;-- -730461. The unit of time. oracle; datediff; or ask your own question. I need to calculate the difference between two dates in Oracle sql and show it in the following format: 'x years y months z days'. ) and the. The dateadd function adds or subtracts a number of specified time units from a given date. That link is not for the Oracle database, it's for JavaDB (Derby). It is important to understand that the DATEDIFF function is both reliable and valid in both cases. e. CODE = 'CONTACT_CLIENT' THEN a. Expressions can contain only one hint. For example, in February 2014, the following returns 1, because January was the most recent calendar month:Last day of current month is actually are not 3/31/20015, it is 3/31/2015 23:59:59. In addition, with DATEDIFF () the column is an argument to the function. How best can this be written? I need to use this in a where clause on DI Studio. 6222691' DECLARE @date2 datetime2 = '2022-01-14 12:32:07. Result: 505 rows listed. DateAdd. Because the precision is 3, the fractional second ‘6789’ is rounded to ‘679’. Viewed 32k times. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). 指定した日付の差異。次の値が有効です。 DD: 差異を日数で計算します。. Feb-N to Mar-N is commonly accepted as a "month". 2. Parameter Description; interval: Required. DATE_ADD () Add time values (intervals) to a date value. Date3(year, month, day) – similar to the ‘Date’ function described above, except that the three parameters are passed in as separate year, month and day values. In short. g. sql. DATE_DIFF = 1. The format argument is optional. Subtracting two dates will return if and only if they are the same year, the same month, the same day, the same hour, the same minute, and the same second. 8494441'. Instead of: datediff ('QUARTER', pr. txt","path":"inst/csv/jarChecksum. DP_MONTH returns the distance between the months capturing the input dates. Syntax:. measure is the name of a measure column. date. Parameter Description; date1, date2: Required. The age in days between the two dates is either 2 or 3 days, but in one case the DATEDIFF function returns an Int data type. ROUND returns date rounded to the unit specified by the format model fmt. Select between two months. The schema is SYSIBM. Push out all due dates by one week. Asked 7 years, 2 months ago. DATEDIFF(expr1,expr2) DATEDIFF() は、ある日付から別の日付までの日数の値として表現された expr1 − expr2 を返します。expr1 および expr2 は、日付または日付時間式です。 値の日付部分のみが計算に使用されます。One practical example of using the DATEDIFF function in SQL Server is in a WHERE clause by selecting all employees in the AdventureWorks2008R2 database whose date of hire was in March 2003. )CREATE OR REPLACE FUNCTION datediff (p_what IN VARCHAR2, p_d1 IN DATE, p_d2 IN DATE) RETURN NUMBER /* Updated to reflect current database and PL/SQL functionality */ AS BEGIN RETURN (p_d2 - p_d1) * CASE UPPER (p_what) WHEN 'SS' THEN 24 * 60 * 60 WHEN 'MI' THEN 24 * 60 WHEN 'HH' THEN 24 ELSE NULL END; END;If this solve your problem, here's the sql server syntax, just replace the variable @yourDate with your column name. Just to clarify SQL server seems to require DATEDIFF (datepart, recentDate, olderDate) as startdate and enddate are a bit nebulous. Hi tom, I want day, month, minute and years difference everyting in seconds. You can write the query in a SQL statement using the DATEADD and DATEDIFF() function. SQL Server has a nice function called DateDiff which takes a date part, startdate and enddate. You should consider how many. If either expression is a character or graphic string, it must not be a CLOB. HQL And datediff() Functions. SYSTIMESTAMP). EOMONTH (date [,months to add) Returns the last do of the month with an optional parameter to add months (+ or -). months_between/120 = decades_between. One option that avoids needing to add EndDate + 23:59:59. date_part is the part of. The system always returns a positive number regardless of.